Question

3. Calculate and insert the proper values to complete the following table: 8pts) [H+M pH Acidic or Basic [OH-M Solution 8.21 POH 1.78 x 10 3.70 x 10-2 4. Give definitions of an Arrhenius acid, a Bronsted-Lowry acid, and a Lewis acid. (3pts) 5. Write the two reactions for the complete dissociation of H.SO., a polyprotic acid. 2pts) 6. Calculate the pH of a 0.015 M solution of HBr. Circle your answer. (2pts)

Answer 1

If pH <7 = Acidic, Given por = 8.21 pH > 7 Basic we know that pH + pol = 14 pH = 14 - poli pr 14-8.21 pH = 5.79 PH LY : Acidic -log[mt] = pH " log Cht] =- pH [ht] = antilog (pH) [H"] = LOPH . [ht] = 10-5.79 = 2009. 100.79 30.16x105 [HJ = 1.6x 10-6 we know that CH] [01] = 2014 > Com a ponte dhe te [711] = 0.625x168 [H] = 6.25x10 9

Given pH = 5.79 pH + pH = 147 POH = 14 - pH poh = 14 - 5.79 pole = 8:21 poh>", JPH <7 : Acidic / -log [ht] =pH [ht] = antilog (-pH) 1 [nt] = 10PH [ht] = 10-5.79 = 109.106.79 = 4.6x16-6 [ht] =1,6x10-6 we know that [ht] [ot] = 1014 [OH) = 4014 - 104 - 1916XTES 10-14 [ht] 1.6x 156 [OH) = 6.25 x109

[on] =1-78x109 we know that CH] COH] = 1014 & [44] = 10-14 Tow] O. 56 x 15 1 - 10-14 1.788 109 [H+] = 56 x 10-6 [ot] = 1-788169 poll = -log com] => pole = -108 (1.78X169) = -log (1.78) -log(169) = -0.25 -(-9) lollo) 59-0.25 = 8.75 pol = 8.75 OM + pol = 14 → pH = 14-8-75 = s.as pH <7 Acidic solution

Given [ht] = 3.78 10-12 we know that pH = -log[44] - pH = -log (3:781012) 3-log (3-7) - log (1612) 5-0.57-(-12) log 20 = 12 -0.57 pH = 11.43 PM > 7 pH + pol =14 Basic solution pol = 14 - 11.43 pol = 2.57 [07] = 10-14 10-14 LHI 3.7 Xióta = 0.27X16-2 [OH) = 2.7x10-3