Question

The equipment used for aviation communications emits high-frequency radiowave energy with a wavelength of 0.250 km. What is the energy of exactly one photon of this radiowave radiation? What is the energy of one mole of this radiowave radiation? J/mol

Answer 1

1)

Given:

lambda = 0.250 km = 2.5*10^2 m

use:

E = h*c/lambda

=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(2.5*10^2 m)

= 7.951*10^-28 J

Answer: 7.95*10^-28 J

2)

Energy of 1 mol = energy of 1 photon * Avogadro's number

= 7.951*10^-28*6.022*10^23 J/mol

= 4.788*10^-4 J/mol

Answer: 4.79*10^-4 J/mol