Question

1. Draw the structure of tripalmitin, the triacylglycerol made from glycerol and palmitic acid. CH2-OH CH-OH CH2-OH palmitic acid glycerol 2. Draw the structure of the product when linolenic acid has been completely halogenated with bromine (Bra). linolenic acid 3. Three fats, labeled X, Y, and Z, were analyzed for double bond content and found to have "iodine numbers" of 78, 147, and 180, respectively. Which of the fats was the most saturated?

Answer 1

1) When one molecule of glycerol condense with three molecule of palmitic acid then tripalmitin is formed. It's structure is :

CH C Scum will

2) Bromine add on each double bond to give following product :

н I-0 С — – — c н — с т Br н — c т Br н — c н ннн — с р-С – С – С – С – С – С – С – С – С Т ! н ннннннннннн | Br Br н — c т Br — c т Br н н Scanned with CamScanner

3) X is most saturated because least iodine number means least unsaturation and most saturated.

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