Question

need to know how to read each and determine the structure. Please list out step by step.

Haine UHU somethylated ether 14) Chemical Formula: C, H,40 tithesion brood IR: strong peak 1720cm-1, strong broad 3300cm-1 2H 2H 2H PPM 15) Chemical Formula: CsH8O2 IR: strong peak 1720cm-1, 1650cm-'( hard to see but, all peaks that integrate to 1H are doublet of doublets) Зн Зн 1H 1H PPM

Answer 1

to 8H The molecular formula C Hala! OBE: Tv- 14/413 12-7-5 so, there must be one benzene ring and one double bond (4) 5 (u present Now, as given here, then 1720 cm-1 strmy IR peak is for co sho 3300 cm brood bean is for -OH group Now, the tubulled NAAR spectron will be as follows Chemical chiff multiplicily guyvin kepolin 1.5 ppm d 3.2 ppm 344 4.7 bom TH 4-8 ppm 2H 1.9 ppm bri singlet TH 6.7 ppm 2H 1.2 a d 2H NOW, As benzene proton integration is 41, so, total benzen is doubly substifted 312 ppm, singht is ET 1.5 ppm, d, it is for the group scH- EN 4.1 4 9114 418 S, 24 .. ? Is 7.20 4,8,5 g . so, ? the structm will be - Arş nooi CH3 7.2d to bHA.9, brs 115,1 CH3 CH 01 1 9 thao7q کا:k 5-12, 6.7. de

15. of Hg 02 DBE - 5-82+1 = 6-4 = 2 1720 cm-1 a cao sth. There is no not functionality ) 1650 cm - CEC smi! so, & Now, from LH NMR we got the following dok. Chemic shift multiplicity interrelia 2.2 ppm 2.3 ppm 3H &14 bbm dd 4.6 ppm dd so, the compound will be Holy D2336m H - ww 1 H 1H 446 pbm 44 bou. I.Trochty R. 2 bbon) City . o CH 3 kg (2.3 ppm)