concentration of the unknown acid solution = 0.101 M
Explanation
Concentration NaOH = 0.50 M
volume NaOH added = 10.10 mL
moles NaOH added = (Concentration NaOH) * (volume NaOH added)
moles NaOH added = (0.50 M) * (10.10 mL)
moles NaOH added = 5.05 mmol
moles acid = (moles NaOH added) / 2
moles acid = (5.05 mmol) / 2
moles acid = 2.525 mmol
concentration of acid = (moles acid) / (volume of acid)
concentration of acid = (2.525 mmol) / (25 mL)
concentration of acid = 0.101 M
NaOH solution Add Base 1.00 ml 0.10 mL Base Added 10.10 ml 0.05 mL Experimental Settings...
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am lost woth Titration, please help... i was able tondo my virtual
lab and get the data needed... but i dont understand what to do on
the remaining problems! please help!
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