Given,
a = 2.7 m/s^2
We know that
S = ut + 1/2 at^2
here, s = 85 m ;
85 = 0 + 1/2 x 2.7 t^2
t = sqrt (2 x 85/2.7) = 7.93 m/s^2
Hence, t = 7.93 s
2. An initially stationary cart rolls down an incline with a measured acceleration of 2.7 m/s....
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