A container is filled with 0.57 mole of O 2 at 30 ∘ C and 845 mmHg .What is the volume, in milliliters, of the container?
Solve this using ideal gas equation
PV=nRT
where pressure P= 845 mm Hg = 1.11184 atm
number of moles n= 0.57 mols
Temperature T= 30 C = 273 K+30 = 303 K
Gas constant R = 0.0821 L atm/mol/k
then volume V= ??
V= nRT/P = 0.57 mols*0.0821 L atm/mol/k*303 K/1.11184 atm
= 12.753 Liters
VOlume = 12753 ml
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