5.0 g of solid Al(NO3)3 was added to enough water to make a 100.0 mL solution....
5.0 g of solid Al(NO3)3 was added to enough water to make a
100.0 mL solution. Al(NO3)3 is very soluble in water.
1. Write out the dissolution reaction that occurs when the solid
Al(NO3)3 was added to water.
2. What is the concentration, in Molarity, of Al(NO3)3 once it is
dissolved in the water?
3. If 53 mL of water was added to the original Al(NO3)3 solution
described above, what is the new concentration in Molarity?
4. What is the concentration, in % w/v, of the solution created
when 12.0 g of solid Al(NO3)3 was added to enough water to make a
150.0 mL solution?
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