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Using standard heats of formation calculate AH for 4 FeO (s) + O2 (g) 2 Fe Os (s) AHr of FeO (s) - -272.0 kJ/mol 5 AHT of Fe

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Answer #1

Given:

Hof(FeO(s)) = -272.0 KJ/mol

Hof(O2(g)) = 0.0 KJ/mol

Hof(Fe2O3(s)) = -825.5 KJ/mol

Balanced chemical equation is:

4 FeO(s) + O2(g) ---> 2 Fe2O3(s)

ΔHo rxn = 2*Hof(Fe2O3(s)) - 4*Hof( FeO(s)) - 1*Hof(O2(g))

ΔHo rxn = 2*(-825.5) - 4*(-272.0) - 1*(0.0)

ΔHo rxn = -563 KJ

Answer: -563 KJ

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