Question

Plz answer

1. Calculate the concentration of H30" in a solution that contains 5.0 Identify the solution as acidic, basic, or neutral. A) 2.0x 10-5 M, basic D) 9.0x 10-1 M, acidic 10-10 M OH at 25°C B) 2.0 10-5 M, acidic E) 9.0 10-1 M. basic 2. Calculate the [H3O~] concentration in an aqueous solution with a pH of 9.85 at 25 C c)5.0x 10-10 M, neutral A) 7.1x 10-5 M B) 4.2x 10-10 M C)8.7 10-10 M E) 1.4x 10-10 M D) 6.5 10-5 M 3. Calculate the [OH] concentration for an aqueous solution with a pH of 7.80 A) 6.3 x 107 M E) 4.0 x 104 M B) 1.6 x 10* M c)1.0x 104 M D) 6.20 x 10 M 4. Which of the following is not a conjugate acid/base pair? A) HCIO/CIO E) all of these are conjugate acid base pairs B) H2SO/HSO C) NH NH D) H2O/OH 5. The pOH of a 0.010 M aqueous solution of Ca(OH): is B) 12.00 A) 11.70 D) 12.60 C) 12.30 E) 1.70 6. Which one of the following salts gives an acidic aqueous solution? B) MgBr E) NiCl C) Bal D) KaSO A) RbNO 7. Which one of the following salts gives a basic aqueous solution? B) LiClO D) NaClO C) FeCl E) CaBr A) K2SO 8. The following endothermic reaction is at equilibrium [ 2SO:(g) 2SO2(g) + O2(g) ]. Predict what will happen if the temperature is increased. A) Ke increases D) more SOs(g) is produced C) Ke decreases B) Ke remains the same 9. The hydrogen sulfate or bisul fate ion HSO4 can act as either an acid or a base in water solution. In which of the following equations does HSO4 act as a base? A) HSO4+H20 H2SO4 + OH C) HSO4 OH H2SO4 + 02 B) HSO4+H3O* > SO3 + 2H20 So H30 D) HSO4 H2O 10. Consider the following reaction at equilibrium [ CO(g) +3H:(g) result of adding more CH4(g) in the system is that CH&(g) + H2O(g) ]. The B) more CHa(g) and H2O(g) are produced. D) Ke decreases. A) Ke increases C) more CO(g) and H2(g) are consumed. E) more CO(g) and H2(g) are produced.

Answer 1

working formala p"= -log [H+] or ph -lag (H307] pon - 100 [ pH + poH = 14 pH > 7 means basic solution pH < 7 means acidic solution pH ~ 7 means nutral solution. - acide solution o Given, [611)50 x 10'OM .: pOH = -log (5.0x16") = 9.30 i p = 14-9.30 = 4.70 97 is <7 so it is auidig solution So, - log [hzot) = 4.70 " C"3° 10 = 2X10M So, option B is correct. Given, PM - 9.85 . - log [H30') = 9.85 : [hzot) - 10985 - 14x100M (option E) ③ Giren, pH = 7.80 i poM = 14-p"14-7-80 = 6:20 . -log (OH): 6-20 i row) -10-= 63 XIDM -6-20 - (option A) Conjugate acid-base pair differs only in one proton. An acid removing a profon gives its conjugate bace & a base accepting a proton gives its conjugate acid. HCIO co + H * ! H₂SOg H50A + H+ Acid conjugate : Acid bла () CB NH3 + H+ + N + H2O → H+ + OH ' (base) conjugate au CCA acid i so, all are conjugate acid-base pairs (optim e correct

Hope you got benefited.

Do rate if so.

Thanks,