5. (8 points) Calculate the pH of each of the following aqueous solutions at 25 °C....

Question

Question

science chemistry

Answer 1

Answer #1

At 25°C

PH+PoH=14

PH=14-PoH

PoH =-log[OH]

a)PH =14-(-log[.65×7.3×10^-10])

=14-9.323=4.677

b)PH=14-(-log[3.15×1.76×10^-5])=14-4.256=9.744

C)PH=14-(-log[.82×6.3×10^-5])=14-4.2868=9.7132

d)PH=14-(-log[.100×(2.5×10^-4+5.6×10^-8+3×10^-13)])

=14-4.60

=9.4

Answer 2

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