Heat lost by metal = heat gained by water
i.e. 42.1 g * specific heat of metal * (95.4 - 32.1) K = 42 g * 4.184 J/g.K * (32.1 - 23) oC
i.e. The specific heat of the metal = 0.6 J/g.K
Question 22 (3 points) A 42.1 g piece of metal was heated to 95.4°C and then...
A 42.1 g piece of metal was heated to 95.4°C and then dropped into a beaker containing 42.0 g of water at 23.00°C. When the water and metal come to thermal equilibrium, the temperature is 32.10°C. What is the specific heat capacity of the metal? The specific heat capacity of the water is 4.184 J/(g-K). 0.387 J/(g-K) 0.600 J/(g-K) 0.488 J/(g-K) 0.720 J/(g-K) 0.980 J/(g-K) Previous Page Next Page Page 22 of 24 Submit Quiz 0 of 24 questions saved
We place 88.8 g of a metal at 90.00◦C in 222.2 g of water at 20.00◦C. The water is in a beaker that is also at 20.00◦C. The specific heat of water is 4.184 J K−1 g −1 and the final temperature of both substances and the beaker is 23.00◦C. The heat capacity of the beaker is 0.777 kJ K−1 . What is the specific heat of the metal? (answer 0.861 JK-1g-1)
A piece of metal with a specific heat of 1.29 J/g°C is heated to 126.6°C and then placed in 133.868 g of water which is at a temperature of 10.9 °C. After a minute, the temperature of the water has stopped changing and is now 45.6°C. Assuming that there are no heat losses to the container or surroundings, what is the mass of the piece of metal in grams? Assume that water has a specific heat of 4.184 J/g°C. Enter...
A 29.3 g piece of metal is heated to 97 degree C and dropped into a calorimeter containing 50.0 g of water (specific heat capacity of water is 4.18 J/g degree C) initially at 22.9 degree C. The empty calorimeter has a heat capacity of 125 J/K. the final temperature of the water is 25.96 degree C. Ignoring significant figures., calculate the specific heat of the metal. A) 0.481 J/gK. B) 0.361 J/gK C) 0.120 J/gK D) 0.300 J/gK E)...
Question 3:
(a) (6 points) We place 120.0 g of a metal at 80.00oC in
436.3 g of water at 25.00oC. The water is in a beaker
that is also at 25.00oC. The specific heat of water is
4.184 J K-1 g-1 and the heat capacity of the
beaker is 0.6666 kJ K-1. The specific heat capacity of
the metal is 0.4444 J K-1 mol-1. What is the
final temperature of the metal, the water, and the beaker?
(b) (3...
Question 3 1 pts A 312 g sample of a metal is heated to 257.896 °C and plunged into 200 g of water at a temperature of 20.43 °C. The final temperature of the water is 79.548 °C. Assuming water has a specific heat capacity of 4.184 J/g °C, what is the specific heat capacity of the metal sample, in J/g °C)? Assume no heat loss to the surroundings. Report your response to 3 digits after the decimal.
A piece of iron (400 g) is heated in a flame to 330°C and then plunged into a beaker containing 1000g of water at 20°C. What is the final equilibrium temperature of the water? The specific heat of iron is .451J/g•C° specific heat of water = 4.184 J/g•C°
3. A75.0 g piece of copper metal is initially at 100°C. It is dropped into a coffee cup calorimeter containing 75.0 g of water a a rature of 20.0°c. Assuming that the only heat exchange is between the copper metal and the water (no heat is given to the calorimeter), what is the final temperature of the water. Specific heat of copper 0.387 J/goC
A 50.0 g piece of iron metal is heated to 200. oC. Then, the iron is placed into a water bath which is at 25.0oC. Eventually, both the iron and the water reach a temperature of 30.0oC. Determine the mass of water used in the experiment. (Specific heat for water is 4.184 J/g . oC ; the specific heat for iron is 0.449 J/g . C )
a 312 g sample of a metal is heated to 355.272 c
A 312 g sample of a metal is heated to 355.272 °C and plunged into 200 g of water at a temperature of 45.471 °C. The final temperature of the water is 59.19 °C. Assuming water has a specific heat capacity of 4.184 J/g °C, what is the specific heat capacity of the metal sample, in J/g °C)? Assume no heat loss to the surroundings. Report your response...