A self-contained breathing apparatus uses canisters of potassium
superoxide, KO2, which consumes
the CO2 exhaled by a person and replaces it with oxygen according
to the following reaction:
4KO2(s) + 2CO2(g) → 2K2CO3(s) + 3O2(g)
(a) What mass of KO2 in g is required to convert 6.30 L of CO2
at 21.0 oC and 656 mmHg into O2?
Answer _____________________
(b) What is the rms speed of an O2 molecule at -9.4 oC?

A self-contained breathing apparatus uses canisters of potassium superoxide, KO2, which consumes the CO2 exhaled by...
Potassium superoxide, KO2, reacts with carbon dioxide
to form potassium carbonate and oxygen:
4KO2 + 2CO2 2K2CO3 +
3O2
This reaction makes potassium superoxide useful in a
self-contained breathing apparatus. How much O2 (in
grams) could be produced from 2.45 g of KO2 and 4.62 g
of CO2?
In self-contained breathing devices used by first responders, potassium superoxide, KO2, reacts with exhaled carbon dioxide producing potassium carbonate and oxygen: ___ KO2(s) + ___ CO2(g) → ___ K2CO3(s) + ___ O2(g) (a) Balance the equation. (b) How much O2 could be produced from 85 g KO2?
The reaction between potassium superoxide, KO2, and CO2, 4KO2+2CO2→2K2CO3+3O2 is used as a source of O2 and absorber of CO2 in self-contained breathing equipment used by rescue workers. a). How many moles of O2 are produced when 0.475 mol of KO2 reacts in this fashion? b). How many grams of KO2 are needed to form 8.0 g of O2? c). How many grams of CO2 are used when 8.0 g of O2 are produced?
Potassium superoxide KO2 reacts with carbon dioxide to form potassium carbonate and oxygen 4KO2(s)+2CO2(g)-->2K2CO3(s)+3O2(g) How many moles of O2 will be produced from 2.50 moles KO2 and 1.50 moles of CO2? Please show work using differential analysis
please provide all the steps
7.37. Oxygen for First Responders In self-contained breathing devices used by first responders, potassium superoxide, KO2, reacts with exhaled carbon dioxide to produce potassium carbonate and oxygen: 4 KO,(s) + 2 CO2(g) – 2 K2CO3(s) + 3 O2(g) How much O, could be produced from 85 g KO,?
7.37. Oxygen for First Responders In self-contained breathing devices used by first responders, potassium superoxide, KO9, reacts with exhaled carbon dioxide to produce potassium carbonate and oxygen: 4 KO2s) 2 CO2g)2 K9CO3(s)+3 O2(g) How much O9 could be produced from 85g KOg?
A backup breathing air supply can use potassium superoxide (KO2) to create oxygen gas by the equation shown below. What volume of oxygen gas (in L) will be produced by this reaction if the device contains 56.6 grams of KO2(s)? Assume 298K and 1.00 atm pressure. MW of KO2 is 71.10 g/mole 4 KO2 (s) + 4 CO2 (g) + 2 H2O (g) à 4 KHCO3 (s) + 3 O2 (g)
answer according to text book is 29 g of O2 produced from 85g
, please show all steps in how to solve!
7.37. Oxygen for First Responders In self-contained breathing devices used by first responders, potassium superoxide, KO2, reacts with exhaled carbon dioxide to produce potassium carbonate and oxygen: 4 KO2(s) +2 CO2(g) 2 K9CO3(s) + 3 O2(g) How much O2 could be produced from 85 g KO2?
Sodium peroxide is often used in self-contained breathing devices such as those used in fire emergencies because it reacts with exhaled carbon dioxide to form sodium carbonate and oxygen gas: a. balance the equation ___ Na2O2(s) + _____ CO2 (g) ----> _____ Na2Co3 (s) + O2 (g) b. If you begin with 3.50 g of Na2O2, how many moles of Na2O2 is that? c. If you begin with 3.50 g of Na2O2, how many moles of )2 can be produced...