Question

Draw a free body diagram for the following problem (dont have to solve it)!

In the figure, a climber with a weight of 540 N is held by a belay rope connected to her climbing harness and belay device; the force of the rope on her has a line of action through her center of mass. The indicated angles are θ = 50˚ and φ = 25˚. If her feet are on the verge of sliding on the vertical wall, what is the coefficient of static friction between her climbing shoes and the wall?

Answer 1

Free body diagrain in rope always along the mga /9 م N- Tension rope gravitational force on mars i.e. weight always acts vertically down Normal force, perpendicular to Surface at point of contact force of friction, parallel to surface into components. from diagram 540N of Tension, T Making T= 540 2 595.82N Tsina of o m g = 5400 Normal force, naa sind Ñ N=59508x Sin (25) = 251.81N about centre of mass torque produced by friction force equal to torque produced by Normal force ine.. Nxlcoso = fxl sino but f= MN, then N sino Given 8= 50°) N coso = n sir (or es = coto - Cot (50%) = 0.84