Question

What is the theoretical yield of H2SO4 + BaCl2 ---> BaSO4 + 2HCl

Given data:

Concentration of BaCl2 = 0.20 M

Concentration of H2SO4 = 6 M

volume of H2S04 = 5.00 mL

What is the theoretical expected yield of precipitate as calculated using stoichiometry?

Compare actual yield and theoretical yield. Calculate percent yield.

Data:

Trial 1: Mass of BaSO4 precipitate = 0.191 g

Trial 2: Mass of BaSO4 precipitate = 0.187 g

What is the Millimoles of BaSO4 for trial 1 & 2?

What is the Millimoles of H2SO4 that reacted for trial 1 & 2?

Volume of final solution reacted?

[H2SO4] final solution M for trial 1 & 2?

DATA Gravimetric Determination of Sulfate Ion Trial 1 Mass of BaSO, and filter paper, 8 1.2289 I what is Trial 2 1.218 I the theoretical expected yield Mass of filter paper, 8 1:0319 140519 0.1918 Mass of BaSO, precipitate, & 0.1879 of precipitate as calculated using stoichiometry? . moles of Baso, moles of H2SO, that reacted Volume of final solution reacted, us [HSOJ, final solution, M compare actual Yield and theoretical Yieldo calculate percent yield. In conclusion and comments:

Answer 1

- H₂SO4 + Balls - Basou +240. Ball2] = 0. 00M (H Sou] = 6 M Volume H₂SO4 = 5.00ml Molarity H₂SO4 = moles H₂SO4 - 6M - Volume Volume H₂SO4 X Molarity = moles H₂SO4 IL x 5.00ml x 6 mol - moles H₂SO4 1000ml L moles H₂SO4 = 0.03 moles Imol H₂SO u gives I mol Basou as per reaction. 0.03 mol H₂ Sou will yield 0.03 mol Basou. Mass Basou = moles Basou X Molas mass = 0.03 mol x 233.38 g/mol = 7.0014 a Theoretical expected yield = 7:0014 g Trial 18 Millimoles Basou a mass Basoy x 1000 millimeles. molar mass Basoy Imole. = 0.1919 x 1000 mmol 0.8 18 mmol 233-38 g/mol. I mol Moles H₂ SO 4 ² Moles Basou from equation) So millimoles H. SOy that reacted = 0.818 mmol. Molarity = moles H₂ SO 4 - 6 M volume H₂SO4 Volume H₂SO4 = 0.818 mmol & Imol = 0.000136 L - 6 mol Lt 1000 mmol = 0.136 ml TH, Sou] = mmol H₂SO4 - 0.818 mmol mol x 1000 mb blume H₂SO4 0.136 ml 1000 mmol IL (H₂SO4) = 6.015 mol l 6.015 M. Actual yield: mass of BasOy precipitate = 0.1919 willd Percent gille actual yield x 100 = 0.1919 x 100 = Theoretical yilld 76001g