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Part D The reactant concentration in a second-order reaction was 0.120 M after 290 s and 7.40x10-2 M after 705 s. What is the
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Answer #1

we have:

[A]1 = 0.120 M

[A]2 = 0.0740 M

t = t2 - t1 = 705 s - 290 s = 415 s

use integrated rate law for 2nd order reaction

1/[A]2 = 1/[A]1 + k*t

1/(7.4*10^-2) = 1/(0.12) + k*415

13.51 = 8.333 +k*4.15*10^2

k*4.15*10^2 = 5.18

k = 1.248*10^-2 M-1.s-1

Answer: 1.25*10^-2 M-1.s-1

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