Question

A nylon guitar string has a linear density of 4.46 g/m and is under a tension of 126 N. The fixed supports are D = 72.7 cm apart. The string is oscillating in the standing wave pattern shown in the figure. Calculate the (a) speed, (b) wavelength, and (c) frequency of the traveling waves whose superposition gives this standing wave.

Answer 1

Here ,

linear density , u = 4.46 g/m = 0.00446 Kg/m

T = 126 N

a) speed of wave = sqrt(T/u)

speed of wave = sqrt(126/0.00446)

speed of wave = 168 m/s

b) wavelength = 2 *L

wavelength = 2 * 0.727

wavelength = 1.454 m

c)frequency of waves = speed of wave/wavelength

frequency of waves = 168/1.454

frequency of waves = 115.5 Hz