Question

1. In an experiment similar to Part 1, the temperature of 65.0 grams of solution went from 23.8°C to 28.3°C. How much heat (Joules) accompanied this reaction? Was this reaction exothermic or endothermic? Indicate the sign accordingly. Explain your answer. Heat = Joules 2. The reaction described in question 1 above was the result of 6.35 mmol of limiting reactant. Calculate the molar heat of reaction based on this limited reactant. Heat of Reaction = Joules/mol Heat of Reaction = kJ/mol 3. Medical and nutritional thermochemical quantities are reported in Calories/mol where 1 Calorie = 1000 calories or 1 kilocalorie. Convert your answer in question 2 to Calories/mol of the limiting reactant. Heat of Reaction = _ Calories/mol

Answer 1

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