Question

17

Question 17 Tries remaining Points out of 100 P Flag question If 10.33 mL of the analyte HCIO, is titrated with 5.33 ml of 0.500 M Sr(OH)2, determine the molarity of the analyte solution. Units are required. Multiple attempts are allowed, however, each incorrect attempt results in a 1/5 (20%) point deduction

Answer 1

Balanced chemical equation is:

Sr(OH)2 + 2 HClO4 ---> Sr(ClO4)2 + 2 H2O

Here:

M(Sr(OH)2)=0.5 M

V(Sr(OH)2)=5.33 mL

V(HClO4)=10.33 mL

According to balanced reaction:

2*number of mol of Sr(OH)2 =1*number of mol of HClO4

2*M(Sr(OH)2)*V(Sr(OH)2) =1*M(HClO4)*V(HClO4)

2*0.5*5.33 = 1*M(HClO4)*10.33

M(HClO4) = 0.516 M

Answer: 0.516 M