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In the example, why would we use NaN3 instead of CH3CN? Why choose Na Nz instead of CHE LN? NaN3, CH₃CN Sul/E,

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7.Br Dok na a > N3 SN, product Here this is the tartiarey bromide, after Br elemination it form tartiary carbocation (3° carbhere the nucleophilicity as well as the basic character of N3- is greater than the CH3CN thus N3- give the SN1 and E1 reaction.

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