Question

The table below represents a semiconductor diode's current-voltage relationship associated with a 12 volt power adapter: Last 3 digits/1000+Volt Vol Current 0 2.45 1.1 0 1.9 0.25 0 2.2 0.4 0 2.4 1.1 (volts) x 2.3 1.8 0.15 2 0.3 2.15 0.43 2.5 2.54 1.39 0.8 1.23 Note: The areas that are shaded are to have the volt measurements changed by adding on your last 3 digits of your I. D divided by 1000. For example: The last 3 digits are 123/1000 .123 New volt reading is 2.45+.123 2.573 volts Complete the following 1. Draw a Scatter Diagram of the data above 2. Complete an expansion table. (Carry your values through to 3 decimal places) 3. Solve for your Linear Correlation Coefficient. 4. Determine the Line of Best Fit. 5. Add the Line of Best Fit to your Scatter Diagranm 6. Determine the estimated Standard Error. 7. Explain the results of the Regression Analysis

Answer 1

1.

2.

Voltage (x)Current (y) 1.8 0.15 2 0.3 2.573 0.8 0.43 0.25 1.23 0.4 1.39 2.15 2.023 2.323 2.54 2.523

3.

Correlation coefficient=0.918193

4.

$Line~of~best~fit:\\ \hat{y}=-2.8533&plus;1.5697x\\ 6.~Estimated~standard~error=0.1937\\ 7.~Since~R^2=0.8431 ~i.e.~84.31\%~of~total~variation~in~the~sample~of~the~Current~is~explained~by\\ the~sample~of~voltage~through~this~linear~regression.~Hence~the~fitting~is~good.\\ From~ANOVA~table~we~see~that~p-value~corresponding~regression~equation\\<0.01.~ Hence~regression~equation~is~significant.~It~is~also~seen~that~p-values~of~slope~and~intercept~<0.01~hence~these~are~significantly~present.\\ Again~we~observed~that~observed~values~are~very~closed~to~the~fitted~line~(see~Solution~5)~hence~we~can~use~this~regression~line~for\\ prediction~purpose.$5.