4 a) Molar mass of KOCl =
90.55g
Mass of KOCl taken = 0.61g
Moles of KOCl = 0.61/90.55= 0.00674 moles
Volume of solvent/ solution = 250 ml = 0.25 L
Hence, molarity = moles of solute / volume of solution
M= 0.00674/0.25= 0.027 M (approx)
4 b) see the image attached
4. a) A solution of potassium hypochlorite (KOCI) is prepared by dissolving 0.61 g of potassium...
4. a) A solution of potassium hypochlorite (KOCI) is prepared by dissolving 0.61 g of potassium hypochlorite in water in a 250 cmº volumetric flask and making up to the mark. What is the molarity of the solution? b) A 10 cm3 aliquot of the potassium hypochlorite solution is added to a conical flask containing an excess of potassium iodide thus generating molecular iodine (12) according to the following reaction: KOCI + 2HCl + 2K1 + 3KCl + H2O +...
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(a) Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (FM 214.00) in a 500 mL volumetric flask. Then 50.00 mL of the solution was pipetted into a flask and treated with excess KI (2 g) and acid (10 mL of 0.5 M H2SO4). How many millimoles of I3− are created by the reaction? (b) The triiodide from part (a) reacted with 37.54 mL of Na2S2O3 solution. What is the concentration of the Na2S2O3 solution? (c) A 1.223...
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