A 0.490 kg mass suspended from a spring oscillates with a period of 1.50 s. How...

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Question

A 0.490 kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to chan

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Answer 1

Answer #1

here,

let the mass to be added is m

as the time period is

T = 2pi * sqrt(mass/k)

for time period

T1/T2 = sqrt(m1/m2)

1.50/2 = sqrt((0.490)/(0.490 + m))

solving for m

m = 0.381 Kg

the mass added is 0.381 Kg

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Answer 2

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