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21 of 26 Complete Review | Constants Periodic Table Part A If the volume of wet gas collected over water is 97.0 mL at 20 °C
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Answer #1

Partial pressure of gas = 750mmHg - 17.5mmHg = 732.5mmHg = 732.5/760 atm = 0.9638atm

Number of moles of gas = PV/ RT = 0.9638atm × 97.0×10-3L / (0.0821atm.L/K.mol × 293.15K ) = 0.0038845mol

Volume of gas at STP conditions = 0.0038845mol × 22400ml/mol = 87.0123ml

= 87.0 ml. (Answer )

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