If you have 275 mg of sodium thiosulfate in 20 mL of water, and 14.8 mL of this solution was required to titrate 104 mg of iodine in 20 mL of solution, what is the amount in mg of Na2S2O3 that is required to completely reduce the 104 mg of I2?
Ans :
275 mg of sodium thiosulfate is present in 20 mL of water
so mass of Na2S2O3 present in 14.8 mL of solution will be :
= ( 14.8 mL x 275 mg) / 20 mL
= 203.5 mg
So the amount of Na2S2O3 required to completely reduce 104 mg of I2 is 203.5 mg.
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