Question

An unknown metal has a mass of 32.6 g. When 983 J of heat are added to the sample, the sample temperature changes by 40.2°C. Calculate the specific heat of the unknown metal. Specific heat (J/g* C) Metal potassium 0.750 silver 0.240 lead 0.160 specific heat: J/(g C) barium 0.204 calcium 0.650 What is the possible identity of the metal based on the calcium 0.650 calculated specific heat? O potassium lead silver Ocalcium

Answer 1

Heat energy (Q) is alreatly proportional to mass of substance. Qam 0 Heat energy is airectly proportional to change in temperature, Q <4T -- from 0, @ Qamar » Qamcat Here ' ¿ is called specific neat of Substance Given, Mase of Cutcuon metall m) = 32.63 Heat Ouergy supplied CQ) - 9835 Change in dew perature (4T) - 40.2°C (o)=? Specific heat at weral @emc4T a Cs an api

- 983 J 32.69x40.2 °c 983 32.6*40.2 983 79.00 1310.52 = 0.750J/g.ee specific heat of metal cc)=0-1500/5.00 This matches with specific neat of potassium in lue Table Given, .: The cukrown metal is: potassium (K) option A correct