Question

Many times it is useful re-writing partial differential thermodynamic expressions in different forms using the total differentials for E, H, F. and G. The total differentials of E, H, F, and G are: dE = TDS – PdV + udn dH = TDS + VDP + udn dF = -SDT – PdV + udn dG = -SDT + VdP + udn - Part A Rewrite the following expression in terms of S, T, P, V.1, 11, Q, CAm, and/or Cvm, in their simplest form so that no derivatives appear: OH an) S.P .60 AEC O 2 ? Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining The correct answer does not depend on: S.

Answer 1

Rewrite the following exporession in term of S,T,P,V, M n , a, Cpm and /or Cum in their simplest form so that no derivative appear : Answer u solution since we know dH = Tds + Vap+ udn - (in { given relation! Now This equation partial differentiate with respect to n with constant value of S, P mean since s and P are constant. This ds=0 dp=0 so (come)s, p 0 la spo

so but these derivative value in following equation. ( )s, patates,pt voor het op+ u centrul se = TXO & Vxo + Mx 1 15.P О + IS.P Important What is point. meaning of any derivative a means change in x with respect to y when a and b are con
summary:

First we understand the meaning of ($\left \partial$H/$\left \partial$n)s,p

($\left \partial$H/$\left \partial$n)s,p means change in H with respect to n when S and P are constant.

Since S and P are constant.

So  $\left \partial$S and $\left \partial$P both are 0 with respect to $\left \partial$n.while

( $\left \partial$n/$\left \partial$n)s,p = 1

So we can calculate ($\left \partial$H/$\left \partial$n)s,p using giving relation.