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If enough of a monoprotic acid is dissolved in water to produce a 0.0135 M solution with a pH of 6.71, what is the equilibriu

It says my answer is incorrect but I don't understand why. It said something about forgetting to take into account the autoprotolysis of water
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Answer #1

+ change In pure water 1007 [ht] [or] = 1.00x Let the acid be HA HA (aq) = H+ (aq) + A-lag) CHA C H+ [A-] Initial 0.0135 100x

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