Question

* In 2013, the price of a new car = $ 35000 In 2019. the price of a Same cur - $ 15000 Assume t-O Represent the cost of car if you purchased It new and tal represent the cost of same car when it is one year old 1) Then: Find the depreciation rate when a) t=0 b) t=1 c) t=2 d) t=3 -NmJ e) t = 4 f) t-5 Draw a scatter diagram with time as the independent variable and value as a dependent Variable. 2)

Answer 1

в From year 2013 to 2019, it is 6 years Total Depreciation = $35000 - $15000 = Depreciation per year= $ $ 20,000 3,333.33 5 Time 6 0 1 Depreciation Rate 9.52% 10.53% 11.76% 13.33% 15.38% 18.18% Cost Price (value) Depreciation 35,000 $ 3,333.33 $ 31,666.67 $ 3,333.33 28,333.33 $ 3,333.33 25,000.00 $ 3,333.33 $ 21,666.67 $ 3,333.33 $ 18,333.33 $ 3,333.33 $ 15,000.00 $ S Value $40,000 $35,000 $30,000 $25,000 $20,000 $15,000 $10,000 $5,000 0 1 2 3 4 5 6 7 Time


B 20000 =C2/6 From year 2013 to 2019, it is 6 years 2 Total Depreciation = $35000 - $15000 = 3 Depreciation per year= 4 1) 5 Time Depreciation Rate 6 0 =D6/C6 7 1 =D7/07 8 2 =D8/C8 =D9/09 =D10/C10 11 5 =D11/C11 Cost Price (value) Depreciation 35000 =$C$3 =C6-D6 =$C$3 =C7-D7 =$C$3 =C8-D8 =$C$3 =C9-09 =$C$3 =C10-D10 =$C$3 =C11-D11 9 3

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