Question

(6 points) Find the binding energy per nucleon in J and eV for the three following isotopes, given their atomic masses in u B boron 19.06373 u x10-12 MeV 22C carbon 22.0572097 u x10-12, MeV 52 Fe iron 51.9481147 u x10-12) MeV mhydrogen = 1.007825 u mneutron = 1.008664915 u u = 1.6605 x 10-27 kg

Answer 1

SB m = 19.043734 Protin = 5 neufon = 14 = 5x 1.001825 5.039125 u mass of proton = mass of neuton = 144 poog aaug15 = 14.12130551 u mpt mm = 19.16043 u mass defect am= 19.16043 u-19.063734 = 0.0967ou = 0.09670 X 1.6605 x 1027 AM = 0.16057x100kg BE = smc² = 0.16057x1027 x (3x108) 2 B.E = 1.44519x.10 J Binding enen per nucleon = 1.44519 xoll 0.01681011 19 B.E/A = 0.76 x 1012 ) for in meu B.E = 0.76x10 MeV 10 х х 115 = 0.475X10 A IBE = 4.15 mer 4.75 Mev Simillarly we can calculate for rest two parts