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8. In a reaction, 2A - Products, the concentration of A decreases from 0.5 mol L-1...
1. The following chemical reaction: A → products shows first order kinetics with respect to A; rate = k[A]. Assume k = 10.09 x 10-4 s-1 . If the initial concentration of A was 0.82 mol L-1 and then decreased to 0.11 mol L-1 , how much time elapsed in minutes? 2. Consider the following balanced chemical equation: H2O2 (aq) + 3 I-(aq) + 2 H+(aq) → I3- (aq) + 2 H2O (l) In the first 62.9 seconds of the...
Referen The initial concentration of the reactant in a first-order reaction A → products is 0.528 mol/L and the half-life is 27.0 s. (a) Calculate the concentration of the reactant (in mol/L) 54.0 s after initiation of the reaction. moll (b) How long (in s) would it take for the concentration of the reactant to drop to one eighth its initial value? (e) How long (ins) would it take for the concentration of the reactant to drop to 0.0330 mol/L?...
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you do the 6-12 number 8 is multiple choice
6. The initial rates listed in the table below were determined for the reaction CO(g) + NO2(g) + CO2(g) + NO(g) at varied concentration of the reactants, CO and NO2. Determine the rate law of this reaction. Experiment Initial [CO] (mol/L) Initial [NO] (mol/L) Initial rate (mol/Ls) 5.0x10+ 3.5x10 3.4x10-8 5.0x10+ 7.0x10- 6.8x10-8 1.5x10 3.5x10 1.02x10-7 7. The half-life of the reaction C&H:(8) ► 2CH.g) at constant temperature is independent...
The reaction NO(g) + 7/2 Cl_2(g) rightarrow NOCl(g) is first-order in [Cl2] and second order with respect to [NO]. Under a given set of conditions, the initial rate of this reaction is 6.20 times 10^-6 mol/L s. What is the rate of this reaction if the concentration of NO is doubled and the concentration of Cl_2 is reduced to half the original value? 6.20 times 10^-6 mol/L s 2.48 X 10_5 mol/L s 1.24 times 10^-5 mol/L s 4.96 times...
The half-life of a reaction,
t1/2, is the time it takes for the reactant concentration [A] to
decrease by half. For example, after one half-life the
concentration falls from the initial concentration [A]0 to [A]0/2,
after a second half-life to [A]0/4, after a third half-life to
[A]0/8, and so on. on. For a first-order reaction, the half-life is
constant. It depends only on the rate constant k and not on the
reactant concentration. It is expressed as t1/2=0.693k For a...
It takes 50.5 s for the concentration of reactant A in the second order reaction A ==> Products 0.84 mol L to half of it. to decrease from its initial value [A]o A) What is the rate constant of the reaction? B) What is the concentration of A after 32 s have passed? B) After what time will the concentration of A be [A]o 16?
please help me with both. TIA
The following chemical reaction: A → products shows zero order kinetics with respect to A; rate = k[A]º. if k = 9.65 x 10-3 moll's and the initial concentration of A is 0.622 mol L-1, what is the half life of this reaction in minutes? You have 5 attempts at this question. Remember: if you want to express an answer in scientific notation, use the letter "E". For example "4.32 x 104 should be...
If the concentration of a particular reactant is doubled and the rate of reaction is cut in half, what must be the order of the reaction with respect to that reagent? Enter your answer as an integer.
A certain first-order reaction (A products) has a rate constant of 5.40 10-3 s I at 45 °C How many minutes does it take for the concentration of the reactant, [A], to drop to 6.25% of the original concentration? at 27 °C A certain second-order reaction (B-products) has a rate constant of 1.05x10-3 M 1.s and an initial half-life of 266 s What is the concentration of the reactant B after one half-life?
The following chemical reaction: A → products shows second order kinetics with respect to A; rate = k[A]2. Assume k = 3.40 x 10-4 mol-1 L s-1 . If the initial concentration of A is 0.77 mol L-1, what is the concentration of A (in mol L-1) after 8.69 minutes?