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What is the number of moles of glucose (C6H12O.) in 0.500 L of a 0.40 M solution? 13 Attempts remaining: 2 What volume in L o
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Answer #1

Question 13

No of moles of glucose = 0.5 x 0.4 = 0.2 Moles

Hence 0.2 Moles of glucose present at 0.5 L of 0.4 M glucose.

Question 14

Volume of NaI = 0.405 x 1000 / 0.724 = 559..39 ml

Hence 559.32 ml of 0.724 M NaI contains 0.405 mol.

Question 15

Mass of Mg(NO3)2 = 45 gm

Molar mass of  Mg(NO3)2 = 148.30 g/mol

Moels of Mg(NO3)2 =   45 gm / 148.30 g/mol = 0.30343 Moles

Volume of Mg(NO3)2 = 0.30343 x 1000 / 0.32 = 948.25 ml

948.25 ml of 0.32 M of Mg(NO3)2 contains 45 gm of Mg(NO3)2

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