28. A 0.50 L buffer solution is 0.20 M in HF and 0.40 M in NaF....

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Question

science chemistry

Answer 1

Answer #1

28 V= 0.52 on addition of 0.025 mole kon [HE] = 0.29 it will react with HF [NaF] = 0.4M HF & kon - KF & no Ka CHF) = 1.5x 104

Answer 2

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