If 62.8 g of aspirin (C,H,Oa) is produced from 79.8 g of CyH6O3, what is the...

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Question

science chemistry

Answer 1

Answer #1

1 mole of C7H6O3 gives 1 mole of aspirin.

Number of moles = mass/molar mass

Molar mass of C7H6O3 = 138.12 g/mol

Moles of C7H6O3 = 79.8/138.12

= 0.58 moles

Moles of aspirin formed = 0.58 mol

Molar mass of aspirin = 180.16 g/mol

Mass of aspirin formed = 180.16 g/mol × 0.58 mol

= 104.50 g of aspirin.

Percent yield = (actual yield/theoretical yield) × 100

Percent yield = ( 79.8/104.50)×100

= 76.4%

Answer = 76.4 %

Answer 2

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