Question

3. + 1/6 points Previous Answers SerCP11 22.3.P.018. Use the exact values you enter to make later calculations A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.68) at an angle of = 34.4° with respect to the normal (see figure below). 2.00 cm (a) Find the angle of refraction at the top surface and the angle of incidence at the bottom surface e ana (b) Find the refracted angle at the bottom surface (c) Find the lateral distance d by which the light beam is shifted, cm (d) Calculate the speed of light in the glass. m/s (e) Calculate the time required for the light to pass through the glass block

Answer 1

Given nie 1 t=2cm n2 = 1.68 O = 34.49 The angle ofere fracliom at me top Surface is equal to angle of Amedense at the bottom Sunface. According to Snell's law. m, Sin(i) = n2 Sinly) i=0 = 34.4°; 7,21 m2 = 1.68 1 Sin(34.4) = 1.68 sinir). sin = 0.3363 - Sin (0.3363) = 19.65 Angle of vrefreaction (LY)= 19.65° Surface is equal to angle (6) The oje freached angle at the bottem of Merdance -. Li = 20 = 3440 © The Late Shift d = (2cm x 1032mm) sin li-r) costro = (2x102) Sin (34.4 - 19.65) COD (19.65) = 5.4069 x 10-3m. d = 0.5407cm. a speed of light a glass slab vae = V = 1.785xio m/s 1.68 Time required to me light to pass through glass block Elme - Distance travelled 6487 1 speed of light an glass The distance fravelled by light ray m Siele meglass (AB) ABCI - 2x104 = 0.021 23 m COD COM(19065) time = 6.02123 1.785X1000 = 1.189 3 x 100 Sec -10 time z 11893 x 10 sec

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