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What would the solubility of [Pb(OH)3 ]-(aq) be in 0.100 M Ba(OH)2(s) in the precense of...

What would the solubility of [Pb(OH)3 ]-(aq) be in 0.100 M Ba(OH)2(s) in the precense of excess Pb(OH)2(s)? (hint: involves combining two reactions into a third and solving the equilibrium)

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Answer #1

Pb(OH)2(s) + H2O = [Pb(OH)3 ]-(aq) + H+

[Pb(OH)3 ]-(aq) = Pb 2+ + 3 OH -

AnSHITO 0-1(M) Ba (o)2 Ba 20H Solubity Conctante Kep = [B tOn 1 = (0-D (0.1)2 10 3 Phlo2 () Pb 2+ 20H Ph(o)2H20 PhloH2 ocerdi

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