What is the equilibrium expression for the following system? B2O3(s) + 6HF(g) ↔ 2BF3(g) + 3H2O(g)...
What is the equilibrium expression for the following system? B2O3(s) + 6HF(g) ↔ 2BF3(g) + 3H2O(g)
Question 2 options: a) Kc = [BF3]2 [H2O] / [HF]6 b) Kc = [BF3]2 [H2O]3 / [B2O3][HF]6 c) Kc = [B2O3][HF]6 / [H2O]3 [BO3]2 d) Kc = [BF3]2 [H2O]3 / [HF]6 e) Kc = [BF3]2 [H2O]3 / [HF]
Homework Answers
Kc is defined as concentration of product by concentration of
reactant with each concentration term raised to power that is equal
to its stoichiometric coefficient in balanced equation
pure liquid and solid do not appear in Kc
So, B2O3(s) will not appear in Kc expression.
So,
Kc = [BF3]^2[H2O]^3 / [HF]^6
Answer: d
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What is the equilibrium expression for the following system?
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