Question

Calculate the pH of a 0.01770.0177 M solution of arginine hydrochloride (arginine·HClarginine·HCl, H2Arg+H2Arg+). Arginine has p?apKa values of 1.8231.823 (p?a1pKa1), 8.9918.991 (p?a2pKa2), and 12.0112.01 (p?a3pKa3).

pH=pH=

Calculate the concentration of each species of arginine in the solution.

[H3Arg2+]=[H3Arg2+]=

MM

[H2Arg+]=[H2Arg+]=

MM

[HArg]=[HArg]=

MM

[Arg−]=[Arg−]=

M

Answer 1

acting as and He Argt ² Hang +47 acting as base x2 ² Harg tot Ą Augt + 110 2 as 11 Argt acting as acld & base, was amphotenc so pH = pkan aplan = 1.823 +8.991 25.407. 2) cut] 10-5-407. 2

for Wprotic and he 4t + T t + HA & 4t + со 2 СИ,А7) + СА 1) + Сна) + C). Ска* . Cr2° , а Ско Гнт)3 + K, C3+ 1%, + « ба A hug' Ов) Сну С)3 + касите он како as a Crte) - 1 К. Си*) Crotal Cat23+ ka CAT2 + kaką Cut) t t<a Каказ . - Coral си , кои*)- каркаси) tka, kar Kagi clerominator Coco helve Сис) <a, Сит) + (<a, Ka, Сн) { iKat Isla Себ-чот) (15*13сот чо») , Cs-sas-ч хст-чо?)) - Cs-873 6 8-ая - X10 12011) 6-о хуб*+ - 30 х 5, 6-оохо - [A2) [r3 Argt2) 2 2-3оэлх 613 2 HA12 * [ Arginine), t 6 - ol xfox o-ot-m 2 2 - 395163 5 оно 8 my l4-сах 16° )

CHEAT] 2 Ch Argt ] i 2 x (Arginine) 22-30, X1073 2 C-306747 X x6-0177m o -01 Sozuld. 2-306798x160 0-01769 m. e lo 0177m) HA 2 CH Arg) 2 TA X (Arginine), G-01737 Xiolt xo-078m 2-306747 41013 4. 6. xloom 795 2 CA) 2 (Arg) 2 x x [Arginine), 2 1.49623 6 X 102 2.30795 xoto & o-0177m. = - 15 x 1012 m)