100 mL of a solution with a S.G. of 1.30 is mixed with how many milliliters of another solution with a S.G. of 1.15 to make a solution with a S.G. of 1.20. How many milliliters of this 1.15 solution are used?
How is this worked? Answer should be 200
100 ml solution having SG 1.30
Another solution let it be X having SG 1.15
These 2 combining to form a solution having SG 1.20
Here we have to find out the value of X ...
Using allegation method we can solve the problem easily
100 ml X
1.30 1.15
1.20
0.5 : .10
1 : 2
so that the ratio becomes 1:2
Here 1 corresponds to 100
so automatically X corresponds to 200
100 mL of a solution with a S.G. of 1.30 is mixed with how many milliliters...
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