here,
m1 = 1 kg , m2 = 2 kg
initial speed , u = 12 m/s
let the final speed be v
using conservation of momentum
m1 * u = (m1 + m2) * v
1 * 12 = ( 1 + 2) * v
solving for v
v = 4 m/s
theta = 37 degree
the distance traveled up the incline be s
using conservation of mechanical energy
0.5 * (m1 + m2) * v^2 = (m1 + m2) * g * s * sin(theta)
0.5 * 4^2 = 9.81 * s * sin(37)
solving for s
s = 1.36 m
the distance traveled up the incline is 1.36 m
A block of ya mass is movin9e 12 mis callider w a stationamy 2 va obiect...
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