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A 10 cm x10 cm square loop is bent at a 90° angle. A uniform 0.060 T magnetic field points downward at a 30° angle with respe

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Find the angle between area normal to the two portions of the loop and the magnetic field and use the definition of magnetic flux to find the solution as shown belowArea of half loop = /² x (10cm) 2 = 50cm? = 5x10-3 m2 Angle between area normal to vertical portion of loop and field is O =

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