Balances by half reaction method


i need help balancing the ones with the arrows. Thanks! CHEM1301 - Chemical Principles I Balancing...
need help balancing the 1st equation
then name what type of reaction is occurring for each
equation
A HNO3(aq) + Cu(s) + O2(g) - Cu(NO3)2(aq) + 4H2O(l) +BANO2(g) Cu(NO3)2(aq) + 2 NaOH(aq) - Cu(OH)2(s) +2 NaNO3(aq) rxn. 2 Cu(OH)2(s) - CuO(s) + H2O(l) rxn. 3 rxn. 4 Cuo(s) + H2SO4(aq) CuSO.(aq) + Zn(s) — CuSO4(aq) + H2O(l) + ZnSO4(aq) + Cu(s) rxn. 5
1. How do I read the half reaction table?
2. If im asked for the best reducing agent from Cu+, Ag+, F2, and
Fe3+, where do I look first in the table? before the arrow or after
the arrow?
3. Sometimes a value that has originally a positive (V) from the
table it will have the negative sign in a homework problem, and
viceversa, so the question is, how do I use the positive and
negative signs in respect to...
8. Using the Nernst equation, determine the ratio of
Hg2+ to Cu2+ at equilibrium in an
electrochemical cell in otherwise pure water, when in contact with
Hg(s) and Cu (s)
Potentially useful data: Reaction Hg 2 +2e = Hgº(s) Feste = Fe2 Cu 2 +2e = Cuº(s) 2H + 2e = H2(g) Pb2 +2e=Pbº(s) Ca*2 + 2e = Cdº(s) 1/4 O2(g) + H + = 1/2 H2O 2 02(g) + 2H+ + 2e = H,O2 1/2 NO3 + H +...
need help for half cell potentials pls calculate step by step
(NOTE - Remember that the positive electrode is attached to the red wire and the negative electrode is attached to the black wire.) Electrode Systems Used Anode (oxidation) Negative Cathode (reduction) Positive Measured Potential (V) Positive (Ecu) Copper and silver Cu() - Cu2+ + 2e" Ag+ +1e Ag) 0.432 V Zinc + Silver Zn cs + 2n**+ Zé dat + leº nAg (s) 1.484 V Copper & Zinc Zn(s)...
I need the pH that includes the activities.
< Question 5 of 10 > Attempt 7 - Determine the pH of a solution containing 0.050 M NaOH and 0.045 M KI neglecting activities. pH = 12.7 Determine the pH of the same solution including activities. Activity coefficients at various ionic strengths can be found in this table. pH= about us careers privacy policy terms of use contact us help Activity Coefficients for Aqueous Solutions at 25°C Ion size (a,pm) Ionic...
6. Given a total dissolved lead concentration of
2.0x10-5 M, a total dissolved NTA concentration of
2.0x10-2 M, and a pH of 12.3 (note extreme pH)
a. Under these conditions, what is the dominant form of NTA?
b. Write an equation for total dissolved NTA and for total
dissolved Pb. What assumptions can you make?
c. Calculate the predicted [Pb2+], considering NTA
complexation only?
d. What is the [Pb2+] as predicted by the solubility
of Pb(OH)2(s) at pH 12.3?
e....
7. A low concentration of NTA has equilibrated with
PbCO3(s) at pH 7.00 in a medium having a final
HCO3- concentration of 7.50x10-4
M.
a. Determine [Pb2+].
b. Write out KT and the overall reaction for
KT.
c. What is the ratio of [Pb(NTA)- ] to
[H(NTA)2-] in this solution?
Potentially useful data: Reaction Hg 2 +2e = Hgº(s) Feste = Fe2 Cu 2 +2e = Cuº(s) 2H + 2e = H2(g) Pb2 +2e=Pbº(s) Ca*2 + 2e = Cdº(s) 1/4...
Using the standard reduction potentials listed, calculate the
equilibrium constant for each of the following reactions at 298
K.
A) Fe(s)+Ni2+(aq)→Fe2+(aq)+Ni(s)
Express your answer using two significant figures.
B) Co(s)+2H+(aq)→Co2+(aq)+H2(g)
Express your answer using two significant figures.
C) 10Br−(aq)+2MnO−4(aq)+16H+(aq)→2Mn2+(aq)+8H2O(l)+5Br2(l)
Express your answer using two significant figure.
E°(V) -0.83 +0.88 +1.78 +0.79 Half-Reaction E°(V) Half-Reaction Ag+ (aq) + - Ag(s) +0.80 2 H20(1) + 2 e — H2(8) + 2 OH+ (aq) AgBr(s) + - Ag(s) + Br" (aq) +0.10 HO2...
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Mg2 ] = 0.774 M and [Sn2 ] = 0.0190 M. Standard reduction potentials can be found here. Reduction Half-Reaction Standard Potential Ered° (V) F2(g) + 2e– → 2F–(aq) +2.87 O3(g) + 2H3O+(aq) + 2e– → O2(g) + 3H2O(l) +2.076 Co3+(aq) + e– → Co2+(aq) +1.92 H2O2(aq) + 2H3O+(aq) + 2e– → 2H2O(l) +1.776 N2O(g) + 2H3O+(aq) + 2e– → N2(g) + 3H2O(l) +1.766 Ce4+(aq) + e– → Ce3+(aq)...
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction + O2(9)+4 H (aq)+4e' 2H20) = 1.23 V red Ered Fe+. (аq) Fe3(aq)+e = +0.771 V Answer the following questions about thiss cell Write a balanced equation for the half-reaction that happens at the cathode Write a balanced equation for the half-reaction that happens at the anode Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous...