Question

Be sure to answer all parts. Calculate the molar solubility of Ag2SO4 in each solution below. The Ksp of silver sulfate is 1.5 × 10−5. (a) 0.36 M AgNO3: (b) 0.36 M Na2SO4:

Answer 1

Answert Let s is molar solublity of Ad Soy Ag, soy 249+ S01 com 28 s. Solublity product Kop - A14]> [sak-] - (2012 (s) = 453 ② 0.36 M 0.34M Ag Nos AgNos gives 0.34 M Agt and 0.34 M ng initially Agzsoy = 2481 / + so many 25+ 0.36 s Isp = [ast]? so,?] 1.5x10-5 = $5+0.36% s Since Ksp 's very low so 28 <<< 0.36 1.5810-5 - (0.36)’s 15 = 1.16 X10-4 MI

0.36 M N42.S0y 0.36 M Nasou gives 24 0.36 in Nut and 0.36 m sout Ag 30y = 244) + See on 28 S+0.36 Ksp = Agr)? (5 oz] 1.5 Xlons = 20)? (s+0.36) Jordi Ksp is very low so sac 0.36 1.5 x 10-5 - 48 x 0.36 X 0.36 S = 3.28 X10-3M7