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Hi. can some one please explain me the solution for this question. the correct answer is A. thanks.

Questions 1 & 2 refer to the solubility of lead chromate, PbCrO4: PbCrO4(s) = Pb2+ (aq) + Cro4?- (aq) !? 1. The Ksp for PbCrO


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To find the solubility of lead chromate (PbCro) Given that Ksp = 2.0 x10-16 It will dissociates PbCro (3)=Pb2+ (aq)+Cro,- (aq

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