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GIVEN DATA HEIGHT OF THE BALL, hB= 2.18m DISTANCE oF sErVICE LINE, HEIGHT oF THE NET FRoM GRDUND, hN * 0.95 THE BALL FALLS (2.18 m - 0.95m)- 1.23 m vERTICALLY IN THE TIME THAT TAKES TO TRAVEL 10 m HopIZOUTAD HORIZON TALLY, χ=Vzxt at VERTICALLY, y。vg x t + 2 2. 2 2 cos cse coste SOLVE FOR

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Answer #1

Note pet g=-3.8, So last e Snould be 1. 23o CoS20 Com Parin both eqaa&oos tue get 84.3

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