Question

A sample of helium gas occupies a volume of 8.82 L at 54.0°C and 0.900 atm. If it is desired to increase the volume of the gas sample to 11.1 L, while increasing its pressure to 1.19 atm, the temperature of the gas sample at the new volume and pressure must be ___°C.

Answer 1

According to combined gas law. - Ti P, initial pressure vt initial volume T → initial temperature in Kelvin Py + final pressure V₂ + final volume Tot final temperature in Kelvin

P, = 0-4 atm V, E 8-१२ T = 54273 321K P₂ = 1.19 atm v. = \\IL Tq=? (0. Aatm ) ( 8. ४२) (१.१० १) (111) (327) (१९१०) (11.11 ) x 3R7k (o. patw) ( 8- १२८) T, = 5५५.13 ५१२ T= 5५५ 3 ५९१ - 273 T, = 27१. 13५११०