Question

19) The electron in a hydrogen atom, originally in le in a hydrogen atom, originally in level =9, undergoes a transition to a lower level by Crung a photon of wavelength 384 nm, What is the final level of the electron? (c-3.00 * 10 m/s, -0.626 X 10 *J's, Rw = 2.179 x 10-18 J o doblo 00.10203

Answer 1

wavelength = 384 nm

= 3.84*10^-7 m

Here photon will be emitted

1/lambda = R* (1/nf^2 - 1/ni^2)

R is Rydberg constant. R = 1.097*10^7 m-1

1/lambda = R* (1/nf^2 - 1/ni^2)

1/3.84*10^-7 = 1.097*10^7*(1/nf^2 - 1/9^2)

(1/nf^2 - 1/9^2) = 0.2374

1/nf^2 = 0.2497

nf^2 = 4

nf = 2

Answer: 2