
If 25.00 mL of 0.194 M NaOH is diluted to a volume of 100.0 mL, what...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and the pH of the mixture is measured. Mass of acid weighed out (grams) 0.773 Volume of NaOH required to reach endpoint: (ml) 19.0 pH of the mixture Ihalf neutralized solution 3.54 Calculate the following...
A 25.00-mL volume of commercial hydrogen peroxide solution was diluted to 250.0 mL in a volumetric flask. Then 25.00 mL of the diluted solution were mixed with 200. mL of water and 20. mL of 3 M H2SO4 and titrated with 0.02177 M KMnO4. The first pink color was observed with 27.72 mL of titrant. A blank prepared from water in place of H2O2 required 0.07 mL to give visible pink color. Using the H2O2 reaction in the Analytical Applications...
0.6573 g of potassium iodate is dissolved and diluted to a volume of 100.0 mL. Then 25.00 mL of this stock solution is pipetted into a 100.0 mL volumetric flask which is filled to the mark with water. What is the concentration of the final standard solution in mol/L? Include units in your answer, and round the final answer to the correct number of significant figures.
30) If 176 mL of 1.00 M NaOH is diluted to 1.00 L, what is the molarity of the resulting solution? (YOU MUST SHOW YOUR WORK ON ATTACHED SHEETS) PLACE ANSWER HERE
A 100.0 mL portion of a stock solution was diluted to 600.0 mL. If the resulting solution was 3.00M, what was tge molarity of tve original stock solution?
If 166 mL of 1.00 M NaOH is diluted 1.00 L, what is the molarity of the resulting solution? Please show all work. Please use sig figs in calculations. Please use units in calculations. :)
25.00 mL of 1M NaOH was diluted with 75.78 mL of water. This was used in a titration of 0.984 mg of an unknown acid, and it took 28.45 mL of diluted NaOH to bring this solution to the equivalence point. What is the unkown solid acids molar mass (grams/mole)? What is it's pKa?
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and the pH of the mixture is measured. Mass of acid weighed out (grams) 0.762 Volume of NaOH required to reach endpoint: (ml) 18.0 pH of the mixture (half neutralized solution) 3.15 Calculate the following...
A titration of 25.00 mL of O.1550 M HCl solution with a solution of NaOH of unknown molarity starts at a buret reading for NaOH of 0.33 mL The phenolphthalein indicator turns light pink the acid solution for over 30 seconds at a buret reading of 24.19 mL 2) What was the volume of HCl you started with? 3) How many moles of HCl were in the original solution? 4) Write the balanced chemical equation for the titration reaction. 5)...
What volume (in mL) of 0.150 M NaOH must be added to 100.0 mL of a 0.0500 F solution of fumaric acid (trans-butenedioic acid) to make a buffer of pH 4.50? Ka1 of Fumeric acid = 8.85x10^-4 pKa = 3.05 Ka2 of Fumeric acid = 3.21x10-5