Question

A student titrated 0.180 g of an unknown acid with 0.10 M NaOH solution and the follow data set was obtained: mL of 0.1M NAOH

please ignore question1


Titration Curve 14 12 y 0.2821x +1.9794 R- 0.9328 10 8 6 4 2 0 0 15 30 35 40 Volume of NaOH 25 20 10 5 Hd
0 0
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Answer #1

Question 2.

The acid is diprotic.

Explanation: There are two raises, one at pH 9, the other at pH 11.2

Question 3.

The acid is weak.

Explanation: At pH 9 (> 7), the acid reached the first-equivalence point.

Question 4.

The MW of the acid is 69.231 g/mol

Explanation: The moles of acid = The moles of acid at the first-equivalence point = (26/1000) L * 0.1 mol/L = 0.0026 mol

i.e. The molar mass of the acid = 0.18 g/0.0026 mol = 69.231 g/mol

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