Question

Determine the molar solubility of copper(I) azide (CuN3CuN3) in a solution with a pH of 10.1210.12. Ignore activities. The ?sp for CuN3CuN3 is 4.9×10−94.9×10−9. The ?a for HN3HN3 is 2.2×10−5.

Answer 1

Let molar Solubility of CU M3 = xem CUM Cept + M3 x x ksp= {cut] [M] [cyt] [Mg] keq= THE UCH) 2.23*104 = 7.64101 - - x² = 16.95*15 15 n = 1.34107 s molar Solubility of Cula

pH = -log[ht] 16.12 = -log(H+3 => [ht] = 16-10-12-.586*1617 HNAN HI Horas a ko = [H] [Mg] a nos [NGH] Can Cut & Heag ksp = 4.9*109 Ht+18 MIH Methon, CUN (s) + H tags certa HNB (92) [cat] [HN3] LH+] keq= TH+1 CM ka = IHMI [HH] Ta - [HT] [1] ksp= [cat] [he] kspx t = [H Mo] * {cut] [NA it ka [HA] [MG] [cut] [ HM2] = ked. => keq = 4.94109* 22x10-5 = 2.2371634